Polar rose off center?

Do you guys know of an equation with a polar rose curve not centered on the origin? Thanks very much.

Polar rose off center?
i could try with the four-leafed rose...



say

r = cos(2θ)

r = (cos2θ - sin2θ)

r3 = r2 (cos2θ - sin2θ)



then

(x2 + y2)^(3/2) = (x2 - y2)



to translate it...

we have

((x-h)2 + (y-k)2)3 = ((x-h)2 - (y-k)2)2



then convert it back to polar...



((rcosθ-h)2 + (rsinθ-k)2)3 = ((rcosθ-h)2 - (rsinθ-k)2)2



unfortunately... by this time... the extraction of the function in the proper polar form is not easy...



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Reply:A simple r = cos(theta) curve will result in a circle of radius 1/2 centered about (r,theta) = (1/2,0), which is not centered (0,anything)



Ref: Polar plotter applet